almost 9 years ago
簡單的逆向，輸入字串每四個字元當成 131 進位看
反解的 code:
def rev(x):
s = ''
for i in range(4):
s = chr(x%131) + s
x /= 131
return s
g = [0x0D50ADE5,0x0E302789,0x0ED66F1F,0x0CD463FF,0x0E0D94DD,0x0FA4461F,0x0CD91DA2]
s = ''
for x in g:
s += rev(x)
print s
Flag: ISG{c011isi0n_is_a_thre4t_t0_sec}
