about 4 years ago

簡單的逆向,輸入字串每四個字元當成 131 進位看
反解的 code:

def rev(x):
  s = ''
  for i in range(4):
    s = chr(x%131) + s
    x /= 131
  return s

g = [0x0D50ADE5,0x0E302789,0x0ED66F1F,0x0CD463FF,0x0E0D94DD,0x0FA4461F,0x0CD91DA2]
s = ''
for x in g:
  s += rev(x)
print s

Flag: ISG{c011isi0n_is_a_thre4t_t0_sec}

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